This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1776. Excerpt: ... Ans. The time past was 54 ye.s; and the whole term of years was 99; therefore the time to the expiration of the lease was 45 years: now § of 54 is 36; and 4 of 45 is 36. Solution. Put x for the time past; then, since thewhole term of years was 99, if x the time past be subtracted from 99 the whole time, there will remain 99-- for the 2X time to come j but f of the time past is--; and £ 99--X 296 4X of the tiaie to come is 4 of = i there 1 5 e. 2X 2Q6 4 I 188.--12X lore--= «; therefore 2 x =»--; 3 5-5 therefore 10sr=n88--12a:; therefore 10-f-12--1188, that is, 22,t=ii88; and x the time past = 54 years j therefore 99-- the time to come equals 45 years.: To this problem I shall add two others of the fame nature, without any solution. First, To divide the number $4. into two such parts, that three times one part may be equal rb four times the other. Ans. The parts are 48 and 3 6: for in the first place, 48-1-36=84; and in the next place, three times 48=" 144= four times 36. Second, To divide the number 60 into two such parts, that a seventh part of one may be equal to an eighth part of the other. Ans. The parts are 28 and 32; for in the first place, 28-5-32=60; and in the next place, of 28 equals 4=4of32... VP ROBLEM 8. 33. // is required to divide the number 50 into two such parts, that $, of one part being added to-J. of the, other3 may make 40. Ans. The parts are 20 and 30: for in the first place, 20+30=50; and in the next place, 40s 20, which is 15, added to £ of 30, which is 25, makes 40. Solution. Put x for one part, and consequently 50--x for the other partthen we shall have J of x =--, and 4 of k. 4 50--x= 2-6 but, according to the problem, these two added together ought to make 40; whence we have this equation, 1----= 40: ...
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